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Multicast Delegates in C#
    
Any delegate that has a void return type is a multicast delegate. A multicast delegate can be assigned and invoke multiple methods.
Example: The following code demonstrates how Add() and Multiply() methods can be passed through a multicase delegate.
using System;
using System.Collections.Generic;
using System.Text;
namespace MyMulticastDelegate
{
//this delegate will be used to call more than one
//method at once
public delegate void MulticastDelegate(int x, int y);
//This class contains methods that MyDelegate will point to.
public class MyClass
{
public static void Add(int x, int y)
{
Console.WriteLine("You are in Add() Method");
Console.WriteLine("{0} + {1} = {2}\n", x, y, x + y);
}
public static void Multiply(int x, int y)
{
Console.WriteLine("You are in Multiply() Method");
Console.WriteLine("{0} X {1} = {2}", x, y, x * y);
}
}
class Program
{
static void Main(string[] args)
{
//Create an Instance of MulticastDelegate
//that points to MyClass.Add().
MulticastDelegate del = new MulticastDelegate(MyClass.Add);
//using the same instance of MulticastDelegate
//to call MyClass.Multibly() by adding it to it's
//invocation list.
del += new MulticastDelegate(MyClass.Multiply);
//Invoke Add() and Multiply() methods using the delegate.
//Note that these methods must have a void return vlue
Console.WriteLine("****calling Add() and Multibly() Methods.****\n\n");
del(5, 5);
//removing the Add() method from the invocation list
del -= new MulticastDelegate(MyClass.Add);
Console.WriteLine("\n\n****Add() Method removed.****\n\n");
//this will invoke the Multibly() method only.
del(5, 5);
}
}
}
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The output of example is as follows:
Calling ****Add() and Multiply() methods.****
5+ 5 = 10
5 * 5 = 25
****Add() method removed.****
5 * 5 = 25
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